Hailee Cline

2022-01-20

How do you solve
${x}^{2}-3x-28=0$?

Kaitlynn Noble

Expert

Step 1
${x}^{2}-3x-28=0$
We can first factorise this expression by splitting the middle term and then find the solutions:
$={x}^{2}-7x+4x-28=0$
$=x\left(x-7\right)+4\left(x-7\right)=0$
$=\left(x+4\right)\left(x-7\right)$
Now, we can equate the two factors with zero and find the solutions:

Anabelle Miller

Expert

Step 1
Solve
$y={x}^{2}-3x-28=0$
I use the new Transforming Method. Roots have different signs.
Factor pairs of

This sum is
$3=-b$
Then the 2 real roots are: -4 and 7.
NOTE. By this method, we can avoid the lengthy factoring by grouping and solving the 2 binomials.

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