For each of the piecewise-defined functions in determine whether or not the function is one-to-one, and if it is, determine its inverse function.
Skilled2020-11-09Added 108 answers
Then we get,
Let us consider two numbers
Also let us assume,
(x + y)(x - y) = 0
(x + y) = 0, (x - y) = 0
x = -y, x = y
Therefore for two elements x and -x we have
Hence f is not one-to-one for
Then we get,
f(x) = x
Let us assume for two elements x and y both greater than or equal to zero, their images are same.
So we get,
f(x) = f(y)
x = y
Hence f is one-to-one function.
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