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Quadratic function and equation
Answer & Explanation
2022-01-24Added 14 answers
We know that, the quadr. eqn,
ax2+bx+c=0 will have no real roots ⇔b2−4ac<0
Therefore, in our case, we must have,
∴9p2+6p+1+4p<0, i.e., 9p2+10p+1<0
∴ Case (1):(p+1)<0 and (9p+1)>0, or,
Case (2):(p+1)>0, and (9p+1)<0
Case (1):(p+1)<0 and (9p+1)>0
∴p<−1 and p≻19. This is impossible.
Similarly, in Case (2), we have, p≻1, &, pM−19, or
We conclude that, ∈(−1,−19)
2022-01-25Added 13 answers
2022-01-27Added 437 answers
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