How do you find the vertex of y=2x^{2}+10x+8?

Natasha Henry

Natasha Henry

Answered question

2022-01-23

How do you find the vertex of y=2x2+10x+8?

Answer & Explanation

Kyler Jacobson

Kyler Jacobson

Beginner2022-01-24Added 8 answers

Step 1
Given the equation of parabola in standard form
y=ax2+bx+c; a0
then the x-coordinate of the vertex is
xvertex=b2a
y=2x2+10x+8 is in standard form
with a=2,b=10 and c=8
xvertex=104=52
substitute this value the equation for y-coordinate
yvertex=2(52)2+10(52)+8=92
vertex=(52, 92)
Graph: {2x2+10x+8[10, 10, 5, 5]}

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