Roger Smith

Answered

2021-12-28

To solve: $3{y}^{2}-y-14=0$

Answer & Explanation

David Clayton

Expert

2021-12-29Added 36 answers

Step 1

Determine the quadratic equations

Determine the quadratic equations

chumants6g

Expert

2021-12-30Added 33 answers

Step 1

Given:

All equations of the form

This equation is in standard form:

Multiply -4 times 3.

Multiply -12 times -14.

Add 1 to 168.

Take the square root of 169.

The opposite of -1 is 1.

Multiply 2 times 3.

Now solve the equation

Reduce the fraction

Now solve the equation

Divide -12 by 6

The equation is now solved

karton

Expert

2022-01-09Added 439 answers

Step 1

Split the middle term -y as 6y and -7y

Replace -y with +6y-7y in

The above equation can be written as

Apply distribtive property for first two terms and last two terms,

Again apply distributive property for y(3y-7)+2(3y-7)

y(3y-7)+2(3y-7)=(3y-7)(y+2)

So the factors are (3y-7) and (y+2)

To find the value of y,

Take 3y-7=0

Add 7 on both sides,

3y-7+7=0+7

3y=7

Divide by 3 on both sides,

Take y+2=0

Subtract 2 on both sides,

y-2+2=0-2

y=-2

The factors are

So, the values of y are

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