To find: The value of K such that the equations

reproacht3

reproacht3

Answered question

2021-12-30

To find: The value of K such that the equations 7.6y10=1.1y+12 and 7.6y=1.1y+K are ewuivalent.

Answer & Explanation

Jacob Homer

Jacob Homer

Beginner2021-12-31Added 41 answers

Step 1
To solve
7.6y10=1.1y+12
Add 10 on both sides,
7.6y10+10=1.1y+12+10
Add the like terms,
7.6y+0=1.1y+22
7.6y=1.1y+22
On comparing 7.6y=1.1y+22 and 7.6y=1.1y+22
K=22
The value of K is 22.
Lindsey Gamble

Lindsey Gamble

Beginner2022-01-01Added 38 answers

Lets
karton

karton

Expert2022-01-10Added 613 answers

Step 1
Given: -7.6y-10=-1.1y+12
Multiply both sides by 10
7.6y×1010×10=1.1y×10+12×10
Refine
-76y-100=-11y+120
Add 100 to both sides
-76y-100+100=-11y+120+100
Simplify

-76y=-11y+220
Add 11y to both sides

-76y+11y=-11y+220+11y
Simplify
-65y=220
Divide both sides by -65
65y65=22065
Simplify
y=4413

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