Given the sequence 6,2, 23,29,…,26561; How many terms are there?

Gregory Jones

Gregory Jones

Answered

2021-12-28

Given the sequence 6,2, 23,29,,26561; How many terms are there?

Answer & Explanation

Mason Hall

Mason Hall

Expert

2021-12-29Added 36 answers

Step 1
The first term =a=6
The common ratio =r=second termfirst term=26=13
Let there are n terms.
Step 2
Using the term formula we get:
an=ar(n1)
26561=6(13)(n1)
2656116=(13)(n1)
119683=(13)(n1)
(13)9=(13)(n1)
9=n1
n=10
Answer: 10
Nadine Salcido

Nadine Salcido

Expert

2021-12-30Added 34 answers

26=13 - this is the common ratio
The sequence is:
6,2,23,29,227,281,2243,2729,22187,26561, Number of terms =10Total Sum=29,5246,561
karton

karton

Expert

2022-01-04Added 439 answers

First term a=6
Common ratio r=23=13
Number of terms n=10
Sum of 10 terms
=a(r101)/(r1)=6((1/3)101)/(1/31)=6×3/4(1/3)101)=9/2(1/3)101)

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