A local salesman receives a base salary of $700 monthly. If his total sales receipts...

Given
Base salary of a salesman ${\displaystyle =\mathrm{\$}700}$ monthly
He receives a commission of 9% on the portion of sales over $1900.
Let the total sales ${\displaystyle =x}$
Commission ${\displaystyle =9\mathrm{\%}of(x-1900)}$
His monthly income if his total sales receipt exceeds $1900 is given by
${\displaystyle 700+(x-1900)9\mathrm{\%}}$
If he wants his monthly income $2800 then
${\displaystyle 700+(x-1900)9\mathrm{\%}=2800}$
${\displaystyle 700+(x-1900)\frac{9}{100}=2800}$
${\displaystyle \frac{70000+(x-1900)9}{100}=2800}$
${\displaystyle 7000+(x-1900)9=280000}$
${\displaystyle 7000+9x-17100=280000}$
${\displaystyle 9x=280000+17100-70000}$
${\displaystyle 9x=227100}$
${\displaystyle x=\frac{227100}{9}}$
${\displaystyle x=25233.33}$
Answer: 25233.33

${\displaystyle 2000=700+\left(\frac{6}{100}\right)\cdot (S-1950)}$
${\displaystyle 1300=\left(\frac{6}{100}\right)\cdot (S-1950)}$
${\displaystyle S-1950=\frac{130000}{6}}$
${\displaystyle S=1950+\frac{130000}{6}}$
${\displaystyle S=1950+21666.67}$
${\displaystyle S=23616.67}$

let the total sales be x he gets 11% on sales above 1150 commission = 11%(x-1150) 1900= 700+11%(x-1150) 1900 = 700 +11%x-11 * 11.50 1200 +126.50 =11%x 1426.50=11%x 142650 =11x x=12968