f(x)={x2+2,x≤1.2x2+2,x>1} a) f(-2) b) f(1)

${\displaystyle f\left(x\right)=\{x^2+2,x\le 1}$ This function will take the value for x less than and equal to 1 ........(˙1).
${\displaystyle f\left(x\right)=\{x^2+2,x>1}$ This function will take the value for x greater than 1 ..................(˙2)
(a)In f(-2) value of x is less than 1 so we will put value of x in
${\displaystyle f(-2)=-2^2+2=4+2=6}$
(b)In f(1) value of x is equal to 1 so we will put value of x in (1)
$f(1)=12+2=1+2=3$