York

2021-06-11

${5}^{2}x-2={25}^{3}x-1$

irwchh

We are given: ${5}^{2}x-2={25}^{3}x-1$
Write 25 as ${5}^{2}$ so that each side have the same base ${5}^{2}x-2={\left({5}^{2}\right)}^{3}x-1$
${5}^{2}x-2={5}^{2}\left(3x-1\right)$
By one-to-one property,
2x−2=2(3x−1)
Solve for x:
2x−2=6x−2
−4x−2=−2
−4x=0
x=0

Jeffrey Jordon