York

2021-06-11

irwchh

Skilled2021-06-12Added 102 answers

We are given:
${5}^{2}x-2={25}^{3}x-1$

Write 25 as$5}^{2$ so that each side have the same base
${5}^{2}x-2={\left({5}^{2}\right)}^{3}x-1$

${5}^{2}x-2={5}^{2}(3x-1)$

By one-to-one property,

2x−2=2(3x−1)

Solve for x:

2x−2=6x−2

−4x−2=−2

−4x=0

x=0

Write 25 as

By one-to-one property,

2x−2=2(3x−1)

Solve for x:

2x−2=6x−2

−4x−2=−2

−4x=0

x=0

Jeffrey Jordon

Expert2021-08-11Added 2575 answers

Here is video solution