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Skilled2021-02-04Added 91 answers
limf(x)=−1 Given x→2
limax2−8x=−1 Substitute f(x)=ax2−8x x→2
a22−8(2)=−1 Evaluate the limit by substituting x=2.
4a=15 Add 16 on both sides.
a=154 Divide both sides by 4.
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