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Alyce Wilkinson
2021-02-03
Delorenzoz
Skilled2021-02-04Added 91 answers
limf(x)=−1 Given x→2 limax2−8x=−1 Substitute f(x)=ax2−8x x→2 a22−8(2)=−1 Evaluate the limit by substituting x=2. 4a−16=−1 Simplify. 4a=15 Add 16 on both sides. a=154 Divide both sides by 4.
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