If the line 3x−4y=0 is tangent in the first quadrant to the curve y=x3+k, then value of k is 1/2 1/4 −1/8 −1/2

Hector Arias

Hector Arias

Answered question

2023-03-22

If the line 3x−4y=0 is tangent in the first quadrant to the curve y=x3+k, then value of k is
1/2
1/4
−1/8
−1/2

Answer & Explanation

Lena Navarro

Lena Navarro

Beginner2023-03-23Added 9 answers

y = x 3 + k d y d x = 3 x 2 = 3 4 x = ± 1 2 When  x = 12 , y = 38 ,   ( 1 2 , 3 8 )  lies on the curve  y = x 3 + k 3 8 = 1 8 + k k = 1 4 When  x = 1 2 , y = 3 8 , a n d ( 1 2 , 3 8 )  lies on the curve 3 8 = 1 8 + k k = 1 4 k = 1 4

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