Troy Kaufman

2023-03-13

How to find the vertex of $f\left(x\right)=8-{\left(x+2\right)}^{2}$?

stunaire2dt

Take note that a parabola's typical vertex form is
$\text{XXX}f\left(x\right)=m{\left(x-a\right)}^{2}+b$ with vertex at $\left(a,b\right)$
The given function: $f\left(x\right)=8-{\left(x+2\right)}^{2}$
a straightforward to reorganize into normal vertex shape as
$\text{XXX}f\left(x\right)=\text{}\left(-1\right){\left(x-\text{}\left(-2\right)\right)}^{2}+8$ with vertex at $\left(-2,8\right)$

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