How to graph the line 2 x - 3 y = 0 ?

Solve for ${\displaystyle y}$
${\displaystyle 2x-3y=0}$
${\displaystyle 2x=3y}$
${\displaystyle y=\frac{2}{3}x}$
Consider ${\displaystyle y=mx+b}$ where m is the slope and b is the y-intercept
graph{2/3x [-4.178, 5.824, -2.35, 2.65]}
The ${\displaystyle y}$-intercept is ${\displaystyle 0}$ so there is a point at ${\displaystyle 0,0}$.
The slope is ${\displaystyle \frac{2}{3}}$ so start from ${\displaystyle 0}$ and move up ${\displaystyle 2}$ and to the right ${\displaystyle 3}$ and there is another point.
These points should be connected by a straight line. .