Dylan Chandler

2023-03-08

How to write the equation in slope intercept form given (2, -1) and (-3, 4)?

Julissa Heath

Beginner2023-03-09Added 3 answers

The slope : $m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}=\frac{4+1}{-3-2}=\frac{5}{-5}=-1$

The equation of line in slope-intercept form is $y=mx+c\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}y=-x+c$

The point (2,-1) is on the line. So it will satisfy the equation $\therefore (-1)=(-1)\cdot 2+c\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}c=-1+2=1$ As a result, the line's equation in slope intercept form is $y=-x+1$

The equation of line in slope-intercept form is $y=mx+c\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}y=-x+c$

The point (2,-1) is on the line. So it will satisfy the equation $\therefore (-1)=(-1)\cdot 2+c\phantom{\rule{1ex}{0ex}}\text{or}\phantom{\rule{1ex}{0ex}}c=-1+2=1$ As a result, the line's equation in slope intercept form is $y=-x+1$