How to find equation of line passing through the point P(8,2) with a slope of...

We can use the point-slope formula to find an equation for the line described in the problem. The point-slope formula states: ${\displaystyle (y-y_1)=m(x-x_1)}$
Where ${\displaystyle m}$ is the slope and ${\displaystyle \left(\begin{array}{cc}{x}_1& y_1\end{array}\right)}$ is a point the line passes through.
Substituting the slope and values from the point in the problem gives:
${\displaystyle (y-2)=4(x-8)}$
To convert this equation to slope-intercept form, we can solve it for ${\displaystyle y}$. The slope-intercept form of a linear equation is: ${\displaystyle y=mx+b}$
Where ${\displaystyle m}$ is the slope and ${\displaystyle b}$ is the y-intercept value.
${\displaystyle y-2=4(x-8)}$
${\displaystyle y-2=(4\cdot x)-(4\cdot 8)}$
${\displaystyle y-2=4x-32}$
${\displaystyle y-2+2=4x-32+2}$
${\displaystyle y-0=4x-30}$
${\displaystyle y=4x-30}$