o1je28g

2023-03-03

How to find equation of line passing through the point P(8,2) with a slope of 4?

Nhluvukoj6m

We can use the point-slope formula to find an equation for the line described in the problem. The point-slope formula states: $\left(y-{y}_{1}\right)=m\left(x-{x}_{1}\right)$
Where $m$ is the slope and $\left(\begin{array}{cc}{x}_{1}& {y}_{1}\end{array}\right)$ is a point the line passes through.
Substituting the slope and values from the point in the problem gives:
$\left(y-2\right)=4\left(x-8\right)$
To convert this equation to slope-intercept form, we can solve it for $y$. The slope-intercept form of a linear equation is: $y=mx+b$
Where $m$ is the slope and $b$ is the y-intercept value.
$y-2=4\left(x-8\right)$
$y-2=\left(4\cdot x\right)-\left(4\cdot 8\right)$
$y-2=4x-32$
$y-2+2=4x-32+2$
$y-0=4x-30$
$y=4x-30$

Do you have a similar question?