o1je28g

2023-03-03

How to find equation of line passing through the point P(8,2) with a slope of 4?

Nhluvukoj6m

Beginner2023-03-04Added 6 answers

We can use the point-slope formula to find an equation for the line described in the problem. The point-slope formula states: $(y-{{y}_{1}})={m}(x-{{x}_{1}})$

Where $m$ is the slope and $\left(\begin{array}{cc}{x}_{1}& {y}_{1}\end{array}\right)$ is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

$(y-{2})={4}(x-{8})$

To convert this equation to slope-intercept form, we can solve it for $y$. The slope-intercept form of a linear equation is: $y={m}x+{b}$

Where $m$ is the slope and $b$ is the y-intercept value.

$y-{2}={4}(x-{8})$

$y-{2}=({4}\cdot x)-({4}\cdot {8})$

$y-{2}=4x-32$

$y-{2}+2=4x-32+2$

$y-0=4x-30$

$y={4}x-{30}$

Where $m$ is the slope and $\left(\begin{array}{cc}{x}_{1}& {y}_{1}\end{array}\right)$ is a point the line passes through.

Substituting the slope and values from the point in the problem gives:

$(y-{2})={4}(x-{8})$

To convert this equation to slope-intercept form, we can solve it for $y$. The slope-intercept form of a linear equation is: $y={m}x+{b}$

Where $m$ is the slope and $b$ is the y-intercept value.

$y-{2}={4}(x-{8})$

$y-{2}=({4}\cdot x)-({4}\cdot {8})$

$y-{2}=4x-32$

$y-{2}+2=4x-32+2$

$y-0=4x-30$

$y={4}x-{30}$