Weston Leonard

2023-03-02

How to use the square root property to solve this equation ${\left(2x+3\right)}^{2}=25$?

Mikaela Horn

By obtaining the square root of both terms on either side of the equation, the square root property is demonstrated.
Doing the same for the specified equation
$\sqrt{{\left(2x+3\right)}^{2}}=\sqrt{25}$
$\sqrt{25}=±5$
So,
$\sqrt{{\left(2x+3\right)}^{2}}=±5$
$\left(2x+3\right)=±5$
First solution:
$2x+3=+5$
Isolating $x$
$2x+3-3=+5-3$
$2x=2$
$x=1$
Second solution:
$2x+3=-5$
Isolating $x$
$2x+3-3=-5-3$
$2x=-8$
$x=-4$

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