How to graph y = | - 1 4 x - 1 | ?

determining the location of y=0
${\displaystyle -\frac{1}{4}x-1=0}$
then ${\displaystyle x=-4}$
when ${\displaystyle x\le -4}$
${\displaystyle \left|-\frac{1}{4}x-1\right|=-\frac{1}{4}x-1}$
when ${\displaystyle x>-4}$
${\displaystyle \left|-\frac{1}{4}x-1\right|=\frac{1}{4}x+1}$
both lines 'll be draw
${\displaystyle y=-\frac{1}{4}x-1}$
finding y-intercept when x=0
${\displaystyle y=-1}$ then the point to ubicate ${\displaystyle (0,-1)}$
when y=0
${\displaystyle x=-4}$ the point is ${\displaystyle (-4,0)}$
for ${\displaystyle y=\frac{1}{4}x+1}$
y-intercept is when x=0
${\displaystyle y=1}$ ${\displaystyle (0,1)}$
x-intercept is when y=0
${\displaystyle x=-4}$ ${\displaystyle (-4,0)}$

Everything that is a negative number is a positive number according to absolute value.
I simply draw a net. Then put instead of x a number. For example:
x=0 then y=1
if x=-4 the y=0
Now you can draw a line that goes through this two points. The other part will be mirrored just like
the right side. Let's see.
Let's put instead of x a number -8. Then y=1 just as for the x=0.
Additionally, it is possible to divide this function into two (a bit useless for this particular example).
${\displaystyle f_1:y=-\frac{1}{4}x-1}$ for ${\displaystyle x\ge 0}$
${\displaystyle f_2:y=\frac{1}{4}x+1}$ for ${\displaystyle x<0}$