jeNdarmjeax11tx

2023-02-21

How to graph $3x+2y=2$ by plotting points?

daneetuhxxtj

Beginner2023-02-22Added 8 answers

By first solving for $y$, change the standard equation for a line to the slope-intercept form. Slope-intercept form is $y=mx+b$, where $m$ is the slope and $b$ is the y-intercept.

$3x+2y=2$

Subtract $3x$ from both sides.

$2y=-2-3x$

Divide both sides by $2$.

$y=-\frac{2}{2}-\frac{3}{2}x$

Simplify.

$y=1-\frac{2}{3}x$

Rearrange into slope-intercept form.

$y=-\frac{2}{3}x+1$

Now find two points on the line by choosing values for $x$ and solving for $y$.

$x=0,$ $y=1$

$x=3,$ $y=-1$

Plot the points on a graph and draw a straight line through the two points.

graph{y=-2/3x+1 [-10, 10, -5, 5]}

$3x+2y=2$

Subtract $3x$ from both sides.

$2y=-2-3x$

Divide both sides by $2$.

$y=-\frac{2}{2}-\frac{3}{2}x$

Simplify.

$y=1-\frac{2}{3}x$

Rearrange into slope-intercept form.

$y=-\frac{2}{3}x+1$

Now find two points on the line by choosing values for $x$ and solving for $y$.

$x=0,$ $y=1$

$x=3,$ $y=-1$

Plot the points on a graph and draw a straight line through the two points.

graph{y=-2/3x+1 [-10, 10, -5, 5]}