simplify 120

brizgney58z

brizgney58z

Answered question

2023-02-22

simplify 120

Answer & Explanation

Maximilian Sosa

Maximilian Sosa

Beginner2023-02-23Added 6 answers

1-2sin2θ=sinθcos2x=cos2x-sin2x&cos2x+sin2x=12sin2θ+sinθ-1=02sin2θ+2sinθ-sinθ-1=02sinθsinθ+1-sinθ+1=0sinθ+12sinθ-1=0
sinθ+1=0 or 2sinθ-1=0
sinθ=-1 or sinθ=12
θ0,2π,θ=π6,5π6,3π2

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