chaomeinguyzyp3

2023-02-18

How to graph the equation $y-8=-x$?

Haleigh Russo

Beginner2023-02-19Added 6 answers

$\text{one way is to find the intercepts, that is where the}$

$\text{graph crosses the x and y axes}$

$\u2022\phantom{\rule{1ex}{0ex}}\text{let x = 0, in the equation for y-intercept}$

$\u2022\phantom{\rule{1ex}{0ex}}\text{let y = 0, in the equation for x-intercept}$

$x=0\Rightarrow y-8=0\Rightarrow y=8\leftarrow {\text{y-intercept}}$

$y=0\Rightarrow 0-8=-x\Rightarrow x=8\leftarrow {\text{x-intercept}}$

$\text{plot the points}\phantom{\rule{1ex}{0ex}}(0,8)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}(8,0)$

$\text{draw a straight line through them for graph}$

graph{-x+8 [-20, 20, -10, 10]}

$\text{graph crosses the x and y axes}$

$\u2022\phantom{\rule{1ex}{0ex}}\text{let x = 0, in the equation for y-intercept}$

$\u2022\phantom{\rule{1ex}{0ex}}\text{let y = 0, in the equation for x-intercept}$

$x=0\Rightarrow y-8=0\Rightarrow y=8\leftarrow {\text{y-intercept}}$

$y=0\Rightarrow 0-8=-x\Rightarrow x=8\leftarrow {\text{x-intercept}}$

$\text{plot the points}\phantom{\rule{1ex}{0ex}}(0,8)\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}(8,0)$

$\text{draw a straight line through them for graph}$

graph{-x+8 [-20, 20, -10, 10]}