How to write an equation of the line in standard form that is Perpendicular to 3y-2x=6 and through (-1,2)?

byskupinnag7y

byskupinnag7y

Answered question

2023-02-16

How to write an equation of the line in standard form that is Perpendicular to 3y-2x=6 and through (-1,2)?

Answer & Explanation

Hayley Rosario

Hayley Rosario

Beginner2023-02-17Added 8 answers

The first step to solve this is to transform the original equation into y = m x + b form.
3 y - 2 x = 6
→Add 2 x to both sides
3 y = 2 x + 6
→Divide 3 on both sides
y = 2 3 x + 2
A line that is perpendicular to this equation has a slope that is the polar opposite of the slope of the original equation.
For example if the original equation was y = 2 x + 3 , the slope of the perpendicular line would be - 1 2
So for this problem, the slope of perpendicular line will be - 3 2
Now that you have the slope, you have to solve for the b -value:
y = - 3 2 x + b
2 = - 3 2 ( - 1 ) + b
2 = 3 2 + b
→Subtract 3 2 to both sides
1 2 = b
Now that you have both the b and the m -value, you plug them into the y = m x + b form to get your answer.
y = - 3 2 x + 1 2
Jayla Gross

Jayla Gross

Beginner2023-02-18Added 2 answers

really expert answer!

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?