What is the equation of the line passing through the point (19, 23) and parallel to the line y= 37x + 29?

malaabsologn3v

malaabsologn3v

Answered question

2023-02-10

What is the equation of the line passing through the point (19, 23) and parallel to the line y= 37x + 29?

Answer & Explanation

leoanardig7k

leoanardig7k

Beginner2023-02-11Added 7 answers

Our line has the same slope as the y= 37x + 29 line because its slope equals 37.
m 1 = m 2 = 37
using point slope equation, y y 1 = m ( x x 1 )
y - y 1 = m ( x - x 1 )
y - 23 = 37 ( x - 19 )
y - 23 = 37 x - 703
y = 37 x - 703 + 23
therefore our final answer:
y = 37 x - 680
Afzal2wl

Afzal2wl

Beginner2023-02-12Added 2 answers

We know that, if the slope of the line l 1 is m 1 and the slope of the line l 2 is m 2 then l 1 / / l 2 m 1 = m 2 (parallel lines)
The line l passes through ( 19 , 23 )
Line l is parallel to y = 37 x + 29
Comparing with y = m x + c m = 37
So, the slope of the line l is m = 37
The equation of line #l # passes through ( x 1 , y 1 ) and has slope m is
y - y 1 = m ( x - x 1 ) .,where, ( x 1 , y 1 ) = ( 19 , 23 ) and m = 37
y - 23 = 37 ( x - 19 )
y - 23 = 37 x - 703
y = 37 x - 680

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