There are multiple chickens and rabbits in a cage. There are 72 heads and 200 feet inside of the cage. How many chickens and rabbits are in there?

osadczyttq

osadczyttq

Answered question

2023-01-30

There are multiple chickens and rabbits in a cage. There are 72 heads and 200 feet inside of the cage. How many chickens and rabbits are in there?

Answer & Explanation

x3wolfygri

x3wolfygri

Beginner2023-01-31Added 6 answers

We can create a system of equations to address the issue because we are aware that chickens and rabbits both have one head, two legs, and four legs, respectively.
Assume that r is the number of rabbits and that c is the number of chickens.
The equation can be expressed in word form as follows for heads:
(number of heads per chicken)(number of chickens) + (number of heads per rabbit)(number of rabbits) = (total number of heads)
In algebraic form, this equation would look like this:
1 c + 1 r = 72 or c + r = 72
Similarly for legs, we can write the equation out in word form as:
(number of legs per chicken)(number of chickens) + (number of legs per rabbit)(number of rabbits) = (total number of rabbits)In algebraic form, this equation would look like this:
2 c + 4 r = 200
So now we have our system of equations:
c + r = 72
2 c + 4 r = 200
Now we can use elimination (or substitution) to solve for c and r:
The second equation can be reduced by dividing both sides by 2:
c + 2 r = 100
We can now subtract the first equation from the second equation because the coefficient of c in both equations is now equal to 1:
c + 2 r - ( c + r ) = 100 - 72
c + 2 r - c - r = 28 by the distributive property
By simplifying and combining like-terms, we get:
r = 28
Now we can substitute this value of r into the first equation, c + r = 72 :
c + 28 = 72
c + 28 - 28 = 72 - 28
c = 44
Therefore, there are 44 chickens and 28 rabbits in the cage.

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