Get the answer to "How to solve 2x2−5x+1=3?"

Alaina Durham

Answered question

2022-12-29

How to solve

2 x^{2} - 5 x + 1 = 3

Jacquelyn Watts

Beginner2022-12-30Added 12 answers

Add 3 to each side and subtract it to get:

2 x^{2} - 5 x - 2 = 0

This is in the form:

a x^{2} + b x + c = 0

with

a = 2

b = - 5

and

c = - 2

We can use the quadratic formula to determine the solutions:

x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}

x = \frac{5 \pm \sqrt{{(- 5)}^{2} - 4 (2) (- 2)}}{2 \cdot 2}

x = \frac{5 \pm \sqrt{25 + 16}}{4}

x = \frac{5}{4} \pm \frac{\sqrt{41}}{4}

yegumbi4q0

Beginner2022-12-31Added 3 answers

2 x^{2} - 5 x + 1 = 3

a a a a a a a - 3 a - 3 a a a

Take 3 away from both sides.

2 x^{2} - 5 x - 2 = 0

Use the quadratic formula because this equation cannot be factored.

You can't use 'macro parameter character #' in math mode

a = 2, b = - 5, c = - 2

x = \frac{- (- 5) \pm \sqrt{{(- 5)}^{2} - 4 (2) (- 2)}}{2 \cdot 2}

x = \frac{5 \pm \sqrt{41}}{4}

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