y1i2de1o64w

2022-12-31

A helicopter hovers 40 ft above the ground. Then the helicopter climbs at a rate of 21 ft/s. How to write a rule that represents the helicopter's height h above the ground as a function of time t. What is the helicopter's height after 45 s?

hemelbol26w

Expert

The height of the helicopter at launch is 40. Since this won't change, the height equation will use a constant to represent it.
This can be shown as an additional 21 feet because the helicopter climbs at a speed of 21 feet per second. When t=1, an additional 21 feet is being added to the helicopter's height. When t=2, an additional 42 feet is being added.
Then:
$h=40+21t$
After 45 seconds:
$h=40+21\left(45\right)$
$h=40+945$
$h=985\text{feet}$

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