experimediaisF

2022-11-26

Find volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution

Shiloh Davenport

Expert

M_a = 6.77M - the initial molarity (concentration)
V_a= 15.00 mL - the initial volume
M_b= 1.50 M - the desired molarity (concentration)
V_b= (15.00 + x mL) - the volume of the desired solution
$\left(6.77M\right)\left(15.00mL\right)=\left(1.50M\right)\left(15.00mL+x\right)\phantom{\rule{0ex}{0ex}}101.55MmL=22.5MmL+1.50xM\phantom{\rule{0ex}{0ex}}101.55MmL-22.5MmL=1.50xM\phantom{\rule{0ex}{0ex}}79.05MmL=1.50M\phantom{\rule{0ex}{0ex}}79.05MmL/1.50M=x\phantom{\rule{0ex}{0ex}}52.7mL=x$
59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M

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