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Answered question

2022-11-26

Find volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution

Answer & Explanation

Shiloh Davenport

Shiloh Davenport

Beginner2022-11-27Added 9 answers

M_a = 6.77M - the initial molarity (concentration)
V_a= 15.00 mL - the initial volume
M_b= 1.50 M - the desired molarity (concentration)
V_b= (15.00 + x mL) - the volume of the desired solution
( 6.77 M ) ( 15.00 m L ) = ( 1.50 M ) ( 15.00 m L + x ) 101.55 M m L = 22.5 M m L + 1.50 x M 101.55 M m L 22.5 M m L = 1.50 x M 79.05 M m L = 1.50 M 79.05 M m L / 1.50 M = x 52.7 m L = x
59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M

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