Find volume of concentrated nitric acid (15.8 M) is needed to prepare 4.0 L of a 2.0 M solution

Question

Shiloh Davenport · Accepted Answer

M_a = 6.77M - the initial molarity (concentration)V_a= 15.00 mL - the initial volumeM_b= 1.50 M - the desired molarity (concentration)V_b= (15.00 + x mL) - the volume of the desired solution  (  6.77  M  )  (  15.00  m  L  )  =  (  1.50  M  )  (  15.00  m  L  +  x  )    101.55  M  m  L  =  22.5  M  m  L  +  1.50  x  M    101.55  M  m  L  −  22.5  M  m  L  =  1.50  x  M    79.05  M  m  L  =  1.50  M    79.05  M  m  L      /    1.50  M  =  x    52.7  m  L  =  x59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M