Rocco May

2023-03-11

In the relation Kinetic Energy $={p}^{2}/2m$ (where p is momentum, m is mass ) . If Momentum is raised by 0.1 % what will be the percentage increase in Kinetic Energy

stunaire2dt

Beginner2023-03-12Added 7 answers

Kinetic energy E=P22m∴E∝P2

Percentage increase in kinetic energy = 2(% increase in momentum) = 2(0.1%) = 0.2%.

Percentage increase in kinetic energy = 2(% increase in momentum) = 2(0.1%) = 0.2%.