The specific heats of iodine vapour and solid are 0.031 and 0.055 cal K^−1 g^−1 respectively. If heat of sublimation of iodine is 24 cal g^−1 at 200 degrees C, find its value at 250 degrees C

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Larissa Pacheco · Accepted Answer

I    2    (  s  )  →      I    2    (  g  )    △  H  =  24  c  a  l      g          −      1        a  t      200    o    C    △  C  p  =  (      C    p        )          p      r      o      d      u      c      t        −  (      C    p        )          r      e      a      c      t      a      n      t          △      C    p    =  (      C    p    )      I    2    (  g  )  −  (      C    p    )      I    2    (  s  )  =  0.031  −  0.055  =  −  0.024     c  a  l         K          −      1               g          −      1          △      H                  250        o            C        −  △      H                  200        o            C        =△      C    p    (      T                  250        o            C        −      T                  200        o            C        )    △      H                  250        o            C        =  24  −  0.024  (  523  −  473  )  =  24  −  1.2    ⇒△      H                  250        o            C        =  22.8  c  a  l      g          −      1

The specific heats of iodine vapour and solid are 0.031 and 0.055 cal K^−1 g^−1...

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