How would you determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm?

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Rigoberto Gordon · Accepted Answer

Electric Field is Force per unit charge   E  =  F      /    q Work is the electric potential per unit of charge.   V  =  W      /    q Work is Force x distance   W  =  F  d So    V  =  F  d      /    q  =  F      /    q  d  =  E  d   V  =  E  d

How would you determine the potential difference between two charged parallel plates that are 0.20...

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