Xander Torres

2023-02-25

How would you determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm?

Rigoberto Gordon

Electric Field is Force per unit charge $E=F/q$
Work is the electric potential per unit of charge. $V=W/q$
Work is Force x distance $W=Fd$
So $V=Fd/q=F/qd=Ed$
$V=Ed$

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