Bapilievolia0o0

2023-02-21

A 0.5 kg ball is thrown horizontally from point A with velocity V_A=2m/s. It strikes the smooth inclined plane and bounces. Take coefficient of restitution e =0.6 and g=10m/s^2The speed at which it bounces from the plane is...

Riley Cisneros

Beginner2023-02-22Added 7 answers

$R={V}_{A}t\phantom{\rule{0ex}{0ex}}t=1sec\phantom{\rule{0ex}{0ex}}{v}_{x}=\mathrm{cos}{30}^{\circ}=\sqrt{3}m/s\phantom{\rule{0ex}{0ex}}{v}_{y}=2\mathrm{sin}{30}^{\circ}=1m/s\phantom{\rule{0ex}{0ex}}{a}_{x}=-g\mathrm{cos}{30}^{\circ}=4.9m/{s}^{2}\phantom{\rule{0ex}{0ex}}{a}_{y}=-g\mathrm{cos}{30}^{\circ}=-4.9\sqrt{3}m/{s}^{2}\phantom{\rule{0ex}{0ex}}{v}_{x}={v}_{x}+{a}_{x}t\phantom{\rule{0ex}{0ex}}{v}_{y}={v}_{y}+{a}_{y}t\phantom{\rule{0ex}{0ex}}V=\sqrt{{v}_{x}^{2}+(eVy{)}^{2}}=8.0m/s$