The dielectric strength of air is 3.0*10^5 V/m. A parallel-plate air-capacitor has area 20 cm^2 and plate separation 0.10 mm. Find the maximum rms voltage of an AC source which can be safely connected to this capacitor.

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Joaquin Edwards · Accepted Answer

Potential difference across the capacitor = Ed  =  3  ×      10          −      5        ×  0.1  ×      10          −      3        =  3  ×      10    2    =  300     V    Maximum rms voltage   =      V          2        =      300          2        =  212  V

The dielectric strength of air is 3.0*10^5 V/m. A parallel-plate air-capacitor has area 20 cm^2...

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