Brendan Sellers

2023-02-21

The dielectric strength of air is 3.0*10^5 V/m. A parallel-plate air-capacitor has area 20 cm^2 and plate separation 0.10 mm. Find the maximum rms voltage of an AC source which can be safely connected to this capacitor.

Joaquin Edwards

Beginner2023-02-22Added 6 answers

Potential difference across the capacitor = Ed

$=3\times {10}^{-5}\times 0.1\times {10}^{-3}=3\times {10}^{2}=300\text{}V\phantom{\rule{0ex}{0ex}}\text{Maximum rms voltage}=\frac{V}{\sqrt{2}}=\frac{300}{\sqrt{2}}=212V$

$=3\times {10}^{-5}\times 0.1\times {10}^{-3}=3\times {10}^{2}=300\text{}V\phantom{\rule{0ex}{0ex}}\text{Maximum rms voltage}=\frac{V}{\sqrt{2}}=\frac{300}{\sqrt{2}}=212V$