Question

The length of a rectangle is 4 cm less than twice its width. Its perimeter is 40 cm. Find its length and width.

Solid Geometry
ANSWERED
asked 2021-01-31
The length of a rectangle is 4 cm less than twice its width. Its perimeter is 40 cm. Find its length and width.

Answers (1)

2021-02-01
Let x be the width so that 2x-4 is the length, both in cm.
The perimeter of a rectangle is given by: P=2l+2w
where l is the length and w is the width.
Given a perimeter of 40 cm, we can write: 40=2(2x-4)+2(x)
Solve for x. Divide both sides by 2: 20=(2x-4)+
20=3x-4
24=3x
8=x
So, the dimensions of the rectangle are: length: 2x-4=2(8)-4=12cm
width: x=8 cm
0
 
Best answer

expert advice

Need a better answer?
...