First, we convert the speed from f/s to mi/hr:
\(\displaystyle{\left({76}{f}\frac{{t}}{{s}}\right)}\cdot{\left({1}{m}\frac{{i}}{{5280}}{f}{t}\right)}\cdot{\left({60}\frac{{s}}{{1}}\min\right)}\cdot{\left({60}\frac{\min}{{1}}{h}{r}\right)}\sim{51.82}{m}\frac{{i}}{{h}}{r}\)

So in 3.1 hours, the car will travel: \(\displaystyle{51.82}{m}\frac{{i}}{{h}}\cdot{3.1}{h}\sim{160.6}\) miles

So in 3.1 hours, the car will travel: \(\displaystyle{51.82}{m}\frac{{i}}{{h}}\cdot{3.1}{h}\sim{160.6}\) miles