Question

Let S be an ordered set and A is a nonempty subset such that sup A exists. Suppose there is a B⊂A such that whenever x∈A there is a y∈B such that x≤y. Show that supB exists and supB=supA.

Analyzing functions
ANSWERED
asked 2020-11-30
Let S be an ordered set and A is a nonempty subset such that sup A exists. Suppose there is a \(\displaystyle{B}⊂{A}\) such that whenever \(\displaystyle{x}∈{A}\) there is a \(\displaystyle{y}∈{B}\) such that \(\displaystyle{x}≤{y}\). Show that \(\displaystyle\supset{B}\) exists and \(\displaystyle\supset{B}=\supset{A}\).

Answers (1)

2020-12-01
Given that B ⊂ A. Since sup (A) exist therefore A has an upper bound sya a then a is also an upper bound of B. Therefore sup (B) exist and On the order hand for every x ⊂ A there exist y ⊂ B such that x<=y. Therefore x<=y<=sup(B). Hence sup(A)<=sup(B) Therefore from (1) and (2) sup(A)=sup(B).
0
 
Best answer

expert advice

Have a similar question?
We can deal with it in 3 hours
...