Finite Math (Probability/Venn Diagram) 13) A survey revealed that 25% of people are entertained by reading books, 39% are entertained by watching TV, and 36% are entertained by both books and TV. What is the probability that a person will be entertained by either books or TV? Express the answer as a percentage. Is this problem stated correctly? How can 36% of the people be entertained by both books and TV, when only 25% of the people are entertained by reading books? EDIT Here are two other questions from the exam, that the instructor said followed the same logic as the question above. 14) Of the coffee makers sold in an appliance store, 5.0% have either a faulty switch or a defective cord, 1.6% have a faulty switch, and 0.2% have both defects. What is the probability that a coffee maker w

Arendrogfkl

Arendrogfkl

Answered question

2022-11-20

Finite Math (Probability/Venn Diagram)
13) A survey revealed that 25% of people are entertained by reading books, 39% are entertained by watching TV, and 36% are entertained by both books and TV. What is the probability that a person will be entertained by either books or TV? Express the answer as a percentage.
Is this problem stated correctly? How can 36% of the people be entertained by both books and TV, when only 25% of the people are entertained by reading books?
EDIT
Here are two other questions from the exam, that the instructor said followed the same logic as the question above.
14) Of the coffee makers sold in an appliance store, 5.0% have either a faulty switch or a defective cord, 1.6% have a faulty switch, and 0.2% have both defects. What is the probability that a coffee maker will have a defective cord? Express the answer as a percentage.
15) A survey of senior citizens at a doctor's office shows that 42% take blood pressure-lowering medication, 45% take cholesterol-lowering medication, and 13% take both medications. What is the probability that senior citizen takes either blood pressure-lowering or cholesterol-lowering medication? Express the answer as a percentage.

Answer & Explanation

Lena Gomez

Lena Gomez

Beginner2022-11-21Added 14 answers

The problem is stated correctly. Usually, there'd be a problem: 25% like TV, 75% like books, and 50% are entertained by both. In this case, since 25+39+36=100, I am led to believe that the question should, when stated more rigorously, read:
A survey revealed that 25% of people are entertained only by reading books, 39% are entertained by only by watching TV, and 36% are entertained only by both books and TV. What is the probability that a person will be entertained by either books or TV?
Other than that, the question is fine.
Edit: In my example, i.e., 25% like TV, 75% like books, and 50% are entertained by both,
P r ( T V B o o k s ) = P r ( T V ) + P r ( B o o k s ) P r ( T V B o o k s ) P r ( T V B o o k s ) = 0.25 + 0.75 0.50 = 0.5 = 50 %
Similarly, for your problem,
P r ( T V B o o k s ) = P r ( T V ) + P r ( B o o k s ) P r ( T V B o o k s ) P r ( T V B o o k s ) = 0.25 + 0.39 0.36 = 0.28 = 28 %

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