# Find the slope that is perpendicular to the line 2x−7y=−12

Find the slope that is perpendicular to the line 2x−7y=−12
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Cullen Petersen
First put the equation in slope-intercept form y=mx+b:
Add −2x to both sides: −7y=−2x−12
Divide everything by $-7:\phantom{\rule{1ex}{0ex}}\text{}\phantom{\rule{1ex}{0ex}}y=\frac{2}{7}x+\frac{12}{7}$
The slope of the given line is $\frac{2}{7}$
The slope of the perpendicular line is the negative reciprocal of the given line: $\phantom{\rule{1ex}{0ex}}\text{}\phantom{\rule{1ex}{0ex}}-\frac{7}{2}$