Nico Patterson
2022-11-20
Answered

What is the z-score of sample X, if $$

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tektonikafrs

Answered 2022-11-21
Author has **15** answers

Clearly, if we have points $({x}_{i},{y}_{i})$ and one of them is $({x}_{i},0)$, we can't perform the devision for that point.

The approach holds as long as there is no zeros in the divisor function values.

The approach holds as long as there is no zeros in the divisor function values.

asked 2022-08-14

What is the z-score of sample X, if $n=169,\mu =33,St.Dev.=39,\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}E\left[X\right]=37$?

asked 2022-08-19

A die is rolled 60 times.

Find the normal approximation to the chance that the face with six spots appears between 9, 10, or 11 times.

The exact chance that the face with six spots appears 9, 10, or 11 times?

my solution; in one roll of the die $P(6\text{spots})=\frac{1}{6}$ In 60 rolls of the die the expected number of times the face with 6 spots appears is given by $E(X)=\text{Mean}=\frac{60}{6}=10$ times.

$SE(6spots)=SD=SQR(\frac{60}{6}\cdot \frac{5}{6})=2.8868$

Applying the normal approximation to the chance that the face with six spots appears 10 times, I obtain the following: mean = 10

$\text{Standard deviation}=2.8868$

Using the continuity correction of 0.5 the following z-scores are found: ${z}_{1}=(9.5-10)/2.8868=-0.1732$ and ${z}_{2}=(10.5-10)/2.8868=0.1732$ Subtracting the cumulative probabilities for the two z-scores gives $0.5688-0.4312=0.1376$ which is the approximate chance that the face with six spots appears 10 times. find the six spots appears between 9,10, or 11?

The exact chance that the face with six spots appears 10 times is found from

$60C10{\left(\frac{1}{6}\right)}^{10\times}{\left(\frac{5}{6}\right)}^{50}=0.137$ find six spots appears 9, 10 or 11 times?

Find the normal approximation to the chance that the face with six spots appears between 9, 10, or 11 times.

The exact chance that the face with six spots appears 9, 10, or 11 times?

my solution; in one roll of the die $P(6\text{spots})=\frac{1}{6}$ In 60 rolls of the die the expected number of times the face with 6 spots appears is given by $E(X)=\text{Mean}=\frac{60}{6}=10$ times.

$SE(6spots)=SD=SQR(\frac{60}{6}\cdot \frac{5}{6})=2.8868$

Applying the normal approximation to the chance that the face with six spots appears 10 times, I obtain the following: mean = 10

$\text{Standard deviation}=2.8868$

Using the continuity correction of 0.5 the following z-scores are found: ${z}_{1}=(9.5-10)/2.8868=-0.1732$ and ${z}_{2}=(10.5-10)/2.8868=0.1732$ Subtracting the cumulative probabilities for the two z-scores gives $0.5688-0.4312=0.1376$ which is the approximate chance that the face with six spots appears 10 times. find the six spots appears between 9,10, or 11?

The exact chance that the face with six spots appears 10 times is found from

$60C10{\left(\frac{1}{6}\right)}^{10\times}{\left(\frac{5}{6}\right)}^{50}=0.137$ find six spots appears 9, 10 or 11 times?

asked 2022-09-14

A negatively-skewed distribution has = 60, = 10. If this entire distribution is transformed into z-scores, describe the shape, mean, and standard deviation for the resulting distribution of z-scores.

asked 2022-07-20

What is the z-score of sample X, if $$

asked 2022-07-01

I need to figure out how to find what proportion of scores fall above a z score of 1.65. I'm having trouble and this hasn't been explained much in class. We have to use a z-table to get the correct scores so I'll supply them here.

In column b (area between mean and the z) the score is 0.4505 for a z score of 1.65. And in column c the score is .0495 for a z score of 1.65. I hope you guys can help me.

How do I figure out what proportion fall above 1.65?

In column b (area between mean and the z) the score is 0.4505 for a z score of 1.65. And in column c the score is .0495 for a z score of 1.65. I hope you guys can help me.

How do I figure out what proportion fall above 1.65?

asked 2022-08-10

What is the z-score of sample X, if $n=64,\mu =56,SD=20,\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}E\left[X\right]=320$?

asked 2022-06-26

Based on historical data, your manager believes that 35% of the company's orders come from first-time customers. A random sample of 103 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.22 and 0.4?

Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations.

Answer = (Enter your answer as a number accurate to 4 decimal places.)