# How do you find vertical and horizontal asymptotes Whenever i am doing curve sketching in calculus class i find it incredibly difficult to find the vertical and horizontal asymptotes and as such i always get up to that point correct and anything from asymptotes and further wrong. Sometimes even my curve is a bit off

How do you find vertical and horizontal asymptotes
Whenever i am doing curve sketching in calculus class i find it incredibly difficult to find the vertical and horizontal asymptotes and as such i always get up to that point correct and anything from asymptotes and further wrong. Sometimes even my curve is a bit off
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lelestalis80d
$2\sqrt{3}+\mathrm{tan}\theta =\sqrt{3}\phantom{\rule{0ex}{0ex}}⇒\mathrm{tan}\theta =\sqrt{3}-2\sqrt{3}\phantom{\rule{0ex}{0ex}}⇒\mathrm{tan}\theta =\sqrt{3}\left(1-2\right)\phantom{\rule{0ex}{0ex}}⇒\mathrm{tan}\theta =-\sqrt{3}\phantom{\rule{0ex}{0ex}}⇒\mathrm{tan}\theta =\mathrm{tan}\frac{2\pi }{3}\phantom{\rule{0ex}{0ex}}⇒\theta =\frac{2\pi }{3}\phantom{\rule{0ex}{0ex}}\theta =\frac{2\pi }{3}+n\pi$