A string is made to vibrate at its third harmonic. The diagram shows two points P and Q at a particular instant in time. Which of the following compares the period of vibration of P and Q? (The string is closed at both ends; P is just before the first maximum antinode and Q is at the next minimum antinode). A. Period of P and Q is the same B. Period of P and Q is different Why is it A not B?

Ricky Arias

Ricky Arias

Answered question

2022-11-18

A string is made to vibrate at its third harmonic. The diagram shows two points P and Q at a particular instant in time. Which of the following compares the period of vibration of P and Q?
(The string is closed at both ends; P is just before the first maximum antinode and Q is at the next minimum antinode).
A. Period of P and Q is the same
B. Period of P and Q is different
Why is it A not B?

Answer & Explanation

Quinten Cervantes

Quinten Cervantes

Beginner2022-11-19Added 13 answers

f ( s ) = 2 F 1 ( 2 s 1 , s 1 2 ; s ; 1 ) = 2 F 1 ( s 1 2 , 2 s 1 ; s ; 1 )
Even for small values of s, we have a nice logarithmic behaviour
log [ f ( s ) ] a b s
Using the data computed for 1 n 100, we have, with R 2 = 0.9999982,
Estimate Standard Error Confidence Interval a 1.640373 0.021344 { 1.598011 , 1.682736 } b 1.379308 0.000367 { 1.380037 , 1.378580 }
and, as you noticed, b is quite close to log ( 4 ) = 1.38629
Pushing the numerical analysis much further, b is closer and closer to ( log ( 4 ) ϵ ). This is normal since
2 F 1 ( 2 s , s ; s ; 1 ) = 4 s
What is interesting is that, if log [ f ( s ) ] is an increasing function going to infinity while, if log [ f ( s ) ] goes through a maximum value.
What is interesting is that
4 s 2 F 1 ( s 1 , 2 s 1 ; s ; 1 ) = 2 + 2 π Γ ( s ) Γ ( s 1 2 )

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