How to solve xy'=2 sqrt(x^2+y^2)+y

How to solve $x{y}^{\prime }=2\sqrt{{x}^{2}+{y}^{2}}+y$?
And what would be the standard form to illustrate this situation? (e.g. ${y}^{\prime }+P\left(x\right)y=Q\left(x\right)$ would be standard form of first order linear differential equation)
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klofnu7c2
The $\mathrm{l}\mathrm{g}$ function is the logarithm to the base $2$ (or binary logarithm), that is, $\mathrm{l}\mathrm{g}\phantom{\rule{thinmathspace}{0ex}}2=1$. Thus
$\mathrm{l}\mathrm{g}\phantom{\rule{thinmathspace}{0ex}}\left(i+i\right)=\mathrm{l}\mathrm{g}\left(2i\right)=\mathrm{l}\mathrm{g}\phantom{\rule{thinmathspace}{0ex}}2+\mathrm{l}\mathrm{g}\phantom{\rule{thinmathspace}{0ex}}i=1+\mathrm{l}\mathrm{g}\phantom{\rule{thinmathspace}{0ex}}i$
By the way, the $\mathrm{l}\mathrm{g}$ function can also be defined by $\mathrm{l}\mathrm{g}\phantom{\rule{thinmathspace}{0ex}}\left(x\right)=\frac{\mathrm{log}x}{\mathrm{log}2}$.