Aden Lambert
2022-11-13
Answered

A person can lift $45kg(\approx 100lb).$ Using the experimental value of the specific gravity for the metal object 8.50 cgs, how many cubic meters of the metal could the person lift (a) in air, (b) in water? How many actual kilograms of metal is this in air, and in water?

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Ryan Davies

Answered 2022-11-14
Author has **18** answers

Mass which the person can lift $=45kg$

$\rho =8500kg/{m}^{3}$

In air, the man can lift $45/8500{m}^{3}$

$=0.0053{m}^{3}$

In water, there is force of buoyance acting on the body from downwards. So, effectively, the density of the body becomes $8500-1000=7500kg/{m}^{3}$

So, find the amount of volume like that in the previous case.

In air, it was 45 kgs

Hope it was helpful!

$\rho =8500kg/{m}^{3}$

In air, the man can lift $45/8500{m}^{3}$

$=0.0053{m}^{3}$

In water, there is force of buoyance acting on the body from downwards. So, effectively, the density of the body becomes $8500-1000=7500kg/{m}^{3}$

So, find the amount of volume like that in the previous case.

In air, it was 45 kgs

Hope it was helpful!

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