log3(1/9)

log3(1/9)

Question
Logarithms
asked 2020-11-27
\(\displaystyle{\log{{3}}}{\left(\frac{{1}}{{9}}\right)}\)

Answers (1)

2020-11-28
\(\displaystyle{\log{{3}}}{\left(\frac{{1}}{{9}}\right)}={\log{{3}}}{\left({3}^{{-{{2}}}}\right)}\) Rewrite \(\displaystyle\frac{{1}}{{9}}\) as a power of 3. =-2 Use the rule \(\displaystyle{\log{{\mathbf{^}}}}{x}={x}.\) -2.
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