(a) dy/dx-1+y^2

glasskerfu

glasskerfu

Answered question

2020-10-28

(a) dydx1+y2

Answer & Explanation

broliY

broliY

Skilled2020-10-29Added 97 answers

Given Differential equations is dydx=1+y2 with y(0)=0.

Now dydx=1+y2dy1+y2=dx(dy1+y2)=dx+C,

where C is a integrating constant arctany=x+C

Now, y(0)=(0)C=0

Hence, the solution is arctany=xy=tanx

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?