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The characteristic equation of this Differential equations is r2+r+3.25=0
Solve this quadratic equation: r=−1±1−132=−1±122=−1±2i32=−(12)±i3
Therefore, the solution is y=C1(e−x2)cos(x3)+C2(e−x2)sin(x3)
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If Lf(t)=F(s), then Lf(4t)
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