I'm thinking of a number. I multiplied it by 8 then subtracted 5, divided by 7, added the result to itself, increased that number by 80% then multiplied by 2/3. The result was 12. What number was I thinking of?

Brittney Lord

Brittney Lord

Answered question

2020-12-22

I'm thinking of a number. I multiplied it by 8 then subtracted 5, divided by 7, added the result to itself, increased that number by 80% then multiplied by 2/3. The result was 12. What number was I thinking of?

Answer & Explanation

Khribechy

Khribechy

Skilled2020-12-23Added 100 answers

Let the number be x.
According to the specified criteria, it multiplied by 8 before subtracting 5, dividing by 7, and adding the outcome to itself. Therefore, the quantity becomes
(8x57)+(8x+57)
Now, it increased by 80% and then multiplied by 23 gives
23[((8x57)+(8x57))+((8x57)+8x57)(80100)]
Given that the result was 12. Thus, we have
23[((8x57)+(8x57)+(8x57+8x57))(80100)]=1223[((8x57)+(8x57))+((8x57)+8x57)(45)]=12((16x10)7)+((16x10)7)(45)=1895((16x10)7)=18(16x10)7=1016x10=7016x=80x=8016x=5
The necessary quantity is therefore 5.

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