Logarithmic inequality: log_(1/3)^2(x^2-3x+2) - log_(1/3)(x-1)>log_(1/3)(x-2) +6

klesstilne1

klesstilne1

Answered question

2022-11-11

Logarithmic inequality: log 1 / 3 2 ( x 2 3 x + 2 ) log 1 / 3 ( x 1 ) > log 1 / 3 ( x 2 ) + 6

Answer & Explanation

retalibry9

retalibry9

Beginner2022-11-12Added 16 answers

log 1 / 3 2 ( x 2 3 x + 2 ) log 1 / 3 ( x 1 ) > log 1 / 3 ( x 2 ) + 6
log 1 / 3 2 ( x 2 3 x + 2 ) log 1 / 3 ( x 1 ) log 1 / 3 ( x 2 ) 6 > 0
log 1 / 3 2 ( x 2 3 x + 2 ) log 1 / 3 ( x 1 ) ( x 2 ) 6 > 0
log 1 / 3 2 ( x 2 3 x + 2 ) log 1 / 3 ( x 2 3 x + 2 ) 6 > 0
Now substitute log 1 / 3 ( x 2 3 x + 2 ) = t

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