To determine

To Describe: A method to measure energy of a photon.

To Describe: A method to measure energy of a photon.

Humberto Campbell
2022-11-04
Answered

To determine

To Describe: A method to measure energy of a photon.

To Describe: A method to measure energy of a photon.

You can still ask an expert for help

Claudia Woods

Answered 2022-11-05
Author has **15** answers

Explanation of Solution

Introduction:

Light is composed of small packets of energy. Each packet is called a photon.

As per Planck-Einstein’s relation:

$E=hv$

Here, E is the energy of the photon, h is the Planck’s constant and v represents the frequency of the photon.

The energy of a photon can be measured using this relation.

To Describe: A method to measure momentum of a photon.

Explanation of Solution

Introduction:

Light is composed of small packets of energy. Each packet is called a photon.

The momentum of a photon can be measured using the following relation:

$p=\frac{E}{c}$Here, E is the energy which can be measured using Planck-Einstein relation and c is the speed of light.

To Describe: The method to measure wavelength of photon.

Explanation of Solution

Introduction:

Light is composed of small packets of energy. Each packet is called a photon.

With the knowledge of momentum, the wavelength of the photon can be measured using the de Broglie’s equation:

$\lambda =\frac{h}{p}$

Where, h is the Planck’s constant.

Introduction:

Light is composed of small packets of energy. Each packet is called a photon.

As per Planck-Einstein’s relation:

$E=hv$

Here, E is the energy of the photon, h is the Planck’s constant and v represents the frequency of the photon.

The energy of a photon can be measured using this relation.

To Describe: A method to measure momentum of a photon.

Explanation of Solution

Introduction:

Light is composed of small packets of energy. Each packet is called a photon.

The momentum of a photon can be measured using the following relation:

$p=\frac{E}{c}$Here, E is the energy which can be measured using Planck-Einstein relation and c is the speed of light.

To Describe: The method to measure wavelength of photon.

Explanation of Solution

Introduction:

Light is composed of small packets of energy. Each packet is called a photon.

With the knowledge of momentum, the wavelength of the photon can be measured using the de Broglie’s equation:

$\lambda =\frac{h}{p}$

Where, h is the Planck’s constant.

asked 2022-04-27

De Broglie's Matter wave equation dividing by zero

I was just thinking about De Broglie's matter wave equation: $\lambda =\frac{h}{p}$ where $p$ is the momentum of the object. But what if the object is at rest? Won't we be dividing by zero? What if we take the limit as momentum tends to zero, won't we start to get noticeable waves? Can someone please explain to me where I went wrong?

I was just thinking about De Broglie's matter wave equation: $\lambda =\frac{h}{p}$ where $p$ is the momentum of the object. But what if the object is at rest? Won't we be dividing by zero? What if we take the limit as momentum tends to zero, won't we start to get noticeable waves? Can someone please explain to me where I went wrong?

asked 2022-09-25

If matter has a wave nature, why is this wave - like characteristic not observable in our daily experiences?

asked 2022-10-02

To determine

A detailed explanation behind larger atomic size with larger Planck’s constant, h.

A detailed explanation behind larger atomic size with larger Planck’s constant, h.

asked 2022-10-21

In an electron microscope, through approximately how many volts of potential difference must electrons be accelerated to achieve a de Broglie wavelength of $1.0\times {10}^{-10}m$?

a) $1.5\times {10}^{-2}V$

b) $1.5\times {10}^{-1}V$

c) $1.5V$

d) $15V$

e) $150V$

a) $1.5\times {10}^{-2}V$

b) $1.5\times {10}^{-1}V$

c) $1.5V$

d) $15V$

e) $150V$

asked 2022-05-15

What is $E$ in below equation? Does it represent total energy or kinetic energy(De-broglie equation for uncharged particle like neutron.)

De-broglie equation for uncharged particle:

$\lambda =\frac{h}{\sqrt{2mE}}$

Where, $\lambda $ = wavelength

$h$ = planks constant

$m$ = mass of uncharged particles

De-broglie equation for uncharged particle:

$\lambda =\frac{h}{\sqrt{2mE}}$

Where, $\lambda $ = wavelength

$h$ = planks constant

$m$ = mass of uncharged particles

asked 2022-10-14

To determine

To Calculate: Momentum of photon by using equation $p=mv$

To Calculate: Momentum of photon by using equation $p=mv$

asked 2022-05-07

Direction of momentum given by the de Broglie relation

$p=mv$

where $m$ is the mass of an electron, and $v$ is its velocity. In this case, since $v$ is a vector, it's clear that the momentum will be also a vector.

However if the momentum is a vector quantity (and it is), what is the direction of the electron's momentum given by the de Broglie relation

$p=h/\lambda \phantom{\rule{0ex}{0ex}}p=\hslash k$

if the Planck constant $h$ is scalar and the wavelength $\lambda $ is also scalar. Similarly the reduced Planck constant $\hslash $ is scalar and the wavenumber $k=2\pi /\lambda $ is also scalar.

$p=mv$

where $m$ is the mass of an electron, and $v$ is its velocity. In this case, since $v$ is a vector, it's clear that the momentum will be also a vector.

However if the momentum is a vector quantity (and it is), what is the direction of the electron's momentum given by the de Broglie relation

$p=h/\lambda \phantom{\rule{0ex}{0ex}}p=\hslash k$

if the Planck constant $h$ is scalar and the wavelength $\lambda $ is also scalar. Similarly the reduced Planck constant $\hslash $ is scalar and the wavenumber $k=2\pi /\lambda $ is also scalar.