Find the 15th term of the geometric sequence 52, 39, 29.25 …

Hayley Mcclain

Hayley Mcclain

Answered question

2022-11-04

Find the 15th term of the geometric sequence 52, 39, 29.25 …

Answer & Explanation

Paskcreessy4k5

Paskcreessy4k5

Beginner2022-11-05Added 20 answers

The first term is a 1 = 52 and the common ratio is 3 4 :
39 52 = 3 13 4 13 = 3 4
29.25 39 = 9.75 3 9.75 4 = 3 4
So in general we can write:
a n = r n - 1 a 0 = ( 3 4 ) n 52
So we find:
a 15 = r 14 a 0 = ( 3 4 ) 14 52 = 3 14 52 4 14
= 4782969 52 268435456 = 248714388 268435456
0.9265

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