I need to find the locus of points (on an Argand diagram) such that: (i) arg(z−(−1−4i))+arg(z−(5+8i))=0 (ii) arg(z−(−1−4i))+arg(z−(5+8i))=pi/2

piopiopioirp

piopiopioirp

Answered question

2022-11-04

I need to find the locus of points (on an Argand diagram) such that:
(i) arg ( z ( 1 4 i ) ) + arg ( z ( 5 + 8 i ) ) = 0
(ii) arg ( z ( 1 4 i ) ) + arg ( z ( 5 + 8 i ) ) = π 2
I could not see a way to solve these problems other than plotting arbitrary points and trying to observe a general pattern.
I am aware that arg ( z ( 1 4 i ) ) arg ( z ( 5 + 8 i ) ) = π 2 is a semicircle, and for other angles, say π 3 or π 4 , part of the arc of a circle, but this is only because I knew that this equation represents the locus of points that made a certain angle between the two complex numbers. I was unable to find a similar representation, however, for (i) and (ii).
I am also interested in whether problems (i) and (ii) can be generalised to any angle between 0 to π. Any help here would be greatly appreciated.

Answer & Explanation

yen1291kp6

yen1291kp6

Beginner2022-11-05Added 12 answers

Denote the points A ( 1 4 i ) , B ( 5 + 8 i ) , M ( z ) .
(i) is equivalent to
arg ( z ( 1 4 i ) ) = arg ( z ( 5 + 8 i ) )
This signifies that the direction from A towards M is opposite to the one from B towards M . The locus of points M ( z ) is the segment A B except A , B .

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